Integrand size = 31, antiderivative size = 284 \[ \int \frac {A+B \log \left (e (a+b x)^n (c+d x)^{-n}\right )}{(g+h x)^4} \, dx=-\frac {B (b c-a d) n}{6 (b g-a h) (d g-c h) (g+h x)^2}-\frac {B (b c-a d) (2 b d g-b c h-a d h) n}{3 (b g-a h)^2 (d g-c h)^2 (g+h x)}+\frac {b^3 B n \log (a+b x)}{3 h (b g-a h)^3}-\frac {B d^3 n \log (c+d x)}{3 h (d g-c h)^3}-\frac {A+B \log \left (e (a+b x)^n (c+d x)^{-n}\right )}{3 h (g+h x)^3}+\frac {B (b c-a d) \left (a^2 d^2 h^2-a b d h (3 d g-c h)+b^2 \left (3 d^2 g^2-3 c d g h+c^2 h^2\right )\right ) n \log (g+h x)}{3 (b g-a h)^3 (d g-c h)^3} \]
-1/6*B*(-a*d+b*c)*n/(-a*h+b*g)/(-c*h+d*g)/(h*x+g)^2-1/3*B*(-a*d+b*c)*(-a*d *h-b*c*h+2*b*d*g)*n/(-a*h+b*g)^2/(-c*h+d*g)^2/(h*x+g)+1/3*b^3*B*n*ln(b*x+a )/h/(-a*h+b*g)^3-1/3*B*d^3*n*ln(d*x+c)/h/(-c*h+d*g)^3+1/3*(-A-B*ln(e*(b*x+ a)^n/((d*x+c)^n)))/h/(h*x+g)^3+1/3*B*(-a*d+b*c)*(a^2*d^2*h^2-a*b*d*h*(-c*h +3*d*g)+b^2*(c^2*h^2-3*c*d*g*h+3*d^2*g^2))*n*ln(h*x+g)/(-a*h+b*g)^3/(-c*h+ d*g)^3
Time = 0.62 (sec) , antiderivative size = 273, normalized size of antiderivative = 0.96 \[ \int \frac {A+B \log \left (e (a+b x)^n (c+d x)^{-n}\right )}{(g+h x)^4} \, dx=-\frac {\frac {2 A}{(g+h x)^3}+\frac {2 B \log \left (e (a+b x)^n (c+d x)^{-n}\right )}{(g+h x)^3}+B (b c-a d) n \left (\frac {h}{(b g-a h) (d g-c h) (g+h x)^2}-\frac {2 h (-2 b d g+b c h+a d h)}{(b g-a h)^2 (d g-c h)^2 (g+h x)}-\frac {2 b^3 \log (a+b x)}{(b c-a d) (b g-a h)^3}+\frac {2 d^3 \log (c+d x)}{(b c-a d) (d g-c h)^3}-\frac {2 h \left (a^2 d^2 h^2+a b d h (-3 d g+c h)+b^2 \left (3 d^2 g^2-3 c d g h+c^2 h^2\right )\right ) \log (g+h x)}{(b g-a h)^3 (d g-c h)^3}\right )}{6 h} \]
-1/6*((2*A)/(g + h*x)^3 + (2*B*Log[(e*(a + b*x)^n)/(c + d*x)^n])/(g + h*x) ^3 + B*(b*c - a*d)*n*(h/((b*g - a*h)*(d*g - c*h)*(g + h*x)^2) - (2*h*(-2*b *d*g + b*c*h + a*d*h))/((b*g - a*h)^2*(d*g - c*h)^2*(g + h*x)) - (2*b^3*Lo g[a + b*x])/((b*c - a*d)*(b*g - a*h)^3) + (2*d^3*Log[c + d*x])/((b*c - a*d )*(d*g - c*h)^3) - (2*h*(a^2*d^2*h^2 + a*b*d*h*(-3*d*g + c*h) + b^2*(3*d^2 *g^2 - 3*c*d*g*h + c^2*h^2))*Log[g + h*x])/((b*g - a*h)^3*(d*g - c*h)^3))) /h
Time = 0.54 (sec) , antiderivative size = 275, normalized size of antiderivative = 0.97, number of steps used = 3, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.097, Rules used = {2948, 93, 2009}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
| \(\displaystyle \int \frac {B \log \left (e (a+b x)^n (c+d x)^{-n}\right )+A}{(g+h x)^4} \, dx\) |
| \(\Big \downarrow \) 2948 |
| \(\displaystyle \frac {B n (b c-a d) \int \frac {1}{(a+b x) (c+d x) (g+h x)^3}dx}{3 h}-\frac {B \log \left (e (a+b x)^n (c+d x)^{-n}\right )+A}{3 h (g+h x)^3}\) |
| \(\Big \downarrow \) 93 |
| \(\displaystyle \frac {B n (b c-a d) \int \left (\frac {b^4}{(b c-a d) (b g-a h)^3 (a+b x)}+\frac {d^4}{(b c-a d) (c h-d g)^3 (c+d x)}+\frac {h^2 \left (\left (3 d^2 g^2-3 c d h g+c^2 h^2\right ) b^2-a d h (3 d g-c h) b+a^2 d^2 h^2\right )}{(b g-a h)^3 (d g-c h)^3 (g+h x)}-\frac {h^2 (-2 b d g+b c h+a d h)}{(b g-a h)^2 (d g-c h)^2 (g+h x)^2}+\frac {h^2}{(b g-a h) (d g-c h) (g+h x)^3}\right )dx}{3 h}-\frac {B \log \left (e (a+b x)^n (c+d x)^{-n}\right )+A}{3 h (g+h x)^3}\) |
| \(\Big \downarrow \) 2009 |
| \(\displaystyle \frac {B n (b c-a d) \left (\frac {h \log (g+h x) \left (a^2 d^2 h^2-a b d h (3 d g-c h)+b^2 \left (c^2 h^2-3 c d g h+3 d^2 g^2\right )\right )}{(b g-a h)^3 (d g-c h)^3}+\frac {b^3 \log (a+b x)}{(b c-a d) (b g-a h)^3}-\frac {d^3 \log (c+d x)}{(b c-a d) (d g-c h)^3}-\frac {h (-a d h-b c h+2 b d g)}{(g+h x) (b g-a h)^2 (d g-c h)^2}-\frac {h}{2 (g+h x)^2 (b g-a h) (d g-c h)}\right )}{3 h}-\frac {B \log \left (e (a+b x)^n (c+d x)^{-n}\right )+A}{3 h (g+h x)^3}\) |
-1/3*(A + B*Log[(e*(a + b*x)^n)/(c + d*x)^n])/(h*(g + h*x)^3) + (B*(b*c - a*d)*n*(-1/2*h/((b*g - a*h)*(d*g - c*h)*(g + h*x)^2) - (h*(2*b*d*g - b*c*h - a*d*h))/((b*g - a*h)^2*(d*g - c*h)^2*(g + h*x)) + (b^3*Log[a + b*x])/(( b*c - a*d)*(b*g - a*h)^3) - (d^3*Log[c + d*x])/((b*c - a*d)*(d*g - c*h)^3) + (h*(a^2*d^2*h^2 - a*b*d*h*(3*d*g - c*h) + b^2*(3*d^2*g^2 - 3*c*d*g*h + c^2*h^2))*Log[g + h*x])/((b*g - a*h)^3*(d*g - c*h)^3)))/(3*h)
3.4.1.3.1 Defintions of rubi rules used
Int[((e_.) + (f_.)*(x_))^(p_)/(((a_.) + (b_.)*(x_))*((c_.) + (d_.)*(x_))), x_] :> Int[ExpandIntegrand[(e + f*x)^p/((a + b*x)*(c + d*x)), x], x] /; Fre eQ[{a, b, c, d, e, f}, x] && IntegerQ[p]
Int[((A_.) + Log[(e_.)*((a_.) + (b_.)*(x_))^(n_.)*((c_.) + (d_.)*(x_))^(mn_ )]*(B_.))*((f_.) + (g_.)*(x_))^(m_.), x_Symbol] :> Simp[(f + g*x)^(m + 1)*( (A + B*Log[e*((a + b*x)^n/(c + d*x)^n)])/(g*(m + 1))), x] - Simp[B*n*((b*c - a*d)/(g*(m + 1))) Int[(f + g*x)^(m + 1)/((a + b*x)*(c + d*x)), x], x] / ; FreeQ[{a, b, c, d, e, f, g, A, B, m, n}, x] && EqQ[n + mn, 0] && NeQ[b*c - a*d, 0] && NeQ[m, -1] && !(EqQ[m, -2] && IntegerQ[n])
Leaf count of result is larger than twice the leaf count of optimal. \(3285\) vs. \(2(275)=550\).
Time = 88.44 (sec) , antiderivative size = 3286, normalized size of antiderivative = 11.57
| method | result | size |
| parallelrisch | \(\text {Expression too large to display}\) | \(3286\) |
| risch | \(\text {Expression too large to display}\) | \(9645\) |
-1/6*(-6*B*ln(b*x+a)*x*a^3*b*d^4*g^2*h^6*n^2+18*B*ln(b*x+a)*x*a^2*b^2*d^4* g^3*h^5*n^2+15*B*x*a*b^3*c^2*d^2*g^2*h^6*n^2-6*B*x^2*a^2*b^2*c*d^3*g*h^7*n ^2+6*B*x^2*a*b^3*c^2*d^2*g*h^7*n^2+6*B*x*ln(e*(b*x+a)^n/((d*x+c)^n))*a^3*b *d^4*g^2*h^6*n-18*B*x*ln(e*(b*x+a)^n/((d*x+c)^n))*a^2*b^2*d^4*g^3*h^5*n+18 *B*x*ln(e*(b*x+a)^n/((d*x+c)^n))*a*b^3*d^4*g^4*h^4*n+6*B*x*a^3*b*c*d^3*g*h ^7*n^2-15*B*x*a^2*b^2*c*d^3*g^2*h^6*n^2-6*B*x*a*b^3*c^3*d*g*h^7*n^2-6*B*x^ 3*ln(e*(b*x+a)^n/((d*x+c)^n))*a^2*b^2*d^4*g*h^7*n+6*B*x^3*ln(e*(b*x+a)^n/( (d*x+c)^n))*a*b^3*d^4*g^2*h^6*n-6*B*ln(b*x+a)*x^3*a*b^3*d^4*g^2*h^6*n^2-6* B*ln(b*x+a)*x^3*b^4*c^2*d^2*g*h^7*n^2+6*B*ln(b*x+a)*x^3*b^4*c*d^3*g^2*h^6* n^2-18*B*ln(b*x+a)*x*a*b^3*d^4*g^4*h^4*n^2+6*B*ln(b*x+a)*x*b^4*c^3*d*g^2*h ^6*n^2-18*B*ln(b*x+a)*x*b^4*c^2*d^2*g^3*h^5*n^2+18*B*ln(b*x+a)*x*b^4*c*d^3 *g^4*h^4*n^2+6*B*ln(h*x+g)*x*a^3*b*d^4*g^2*h^6*n^2-18*B*ln(h*x+g)*x*a^2*b^ 2*d^4*g^3*h^5*n^2+18*B*ln(h*x+g)*x*a*b^3*d^4*g^4*h^4*n^2-6*B*ln(h*x+g)*x*b ^4*c^3*d*g^2*h^6*n^2+18*B*ln(h*x+g)*x*b^4*c^2*d^2*g^3*h^5*n^2+6*B*x^2*ln(e *(b*x+a)^n/((d*x+c)^n))*a^3*b*d^4*g*h^7*n-18*B*x^2*ln(e*(b*x+a)^n/((d*x+c) ^n))*a^2*b^2*d^4*g^2*h^6*n+18*B*x^2*ln(e*(b*x+a)^n/((d*x+c)^n))*a*b^3*d^4* g^3*h^5*n-2*B*ln(b*x+a)*a^3*b*d^4*g^3*h^5*n^2+6*B*ln(b*x+a)*x^3*a^2*b^2*d^ 4*g*h^7*n^2-18*B*ln(h*x+g)*x*b^4*c*d^3*g^4*h^4*n^2-6*B*ln(b*x+a)*x^2*a^3*b *d^4*g*h^7*n^2+18*B*ln(b*x+a)*x^2*a^2*b^2*d^4*g^2*h^6*n^2-18*B*ln(b*x+a)*x ^2*a*b^3*d^4*g^3*h^5*n^2+6*B*ln(b*x+a)*x^2*b^4*c^3*d*g*h^7*n^2-18*B*ln(...
Timed out. \[ \int \frac {A+B \log \left (e (a+b x)^n (c+d x)^{-n}\right )}{(g+h x)^4} \, dx=\text {Timed out} \]
Timed out. \[ \int \frac {A+B \log \left (e (a+b x)^n (c+d x)^{-n}\right )}{(g+h x)^4} \, dx=\text {Timed out} \]
Leaf count of result is larger than twice the leaf count of optimal. 920 vs. \(2 (272) = 544\).
Time = 0.26 (sec) , antiderivative size = 920, normalized size of antiderivative = 3.24 \[ \int \frac {A+B \log \left (e (a+b x)^n (c+d x)^{-n}\right )}{(g+h x)^4} \, dx=\frac {{\left (\frac {2 \, b^{3} e n \log \left (b x + a\right )}{b^{3} g^{3} h - 3 \, a b^{2} g^{2} h^{2} + 3 \, a^{2} b g h^{3} - a^{3} h^{4}} - \frac {2 \, d^{3} e n \log \left (d x + c\right )}{d^{3} g^{3} h - 3 \, c d^{2} g^{2} h^{2} + 3 \, c^{2} d g h^{3} - c^{3} h^{4}} + \frac {2 \, {\left (3 \, a b^{2} d^{3} e g^{2} n - 3 \, a^{2} b d^{3} e g h n + a^{3} d^{3} e h^{2} n - {\left (3 \, c d^{2} e g^{2} n - 3 \, c^{2} d e g h n + c^{3} e h^{2} n\right )} b^{3}\right )} \log \left (h x + g\right )}{{\left (d^{3} g^{3} h^{3} - 3 \, c d^{2} g^{2} h^{4} + 3 \, c^{2} d g h^{5} - c^{3} h^{6}\right )} a^{3} - 3 \, {\left (d^{3} g^{4} h^{2} - 3 \, c d^{2} g^{3} h^{3} + 3 \, c^{2} d g^{2} h^{4} - c^{3} g h^{5}\right )} a^{2} b + 3 \, {\left (d^{3} g^{5} h - 3 \, c d^{2} g^{4} h^{2} + 3 \, c^{2} d g^{3} h^{3} - c^{3} g^{2} h^{4}\right )} a b^{2} - {\left (d^{3} g^{6} - 3 \, c d^{2} g^{5} h + 3 \, c^{2} d g^{4} h^{2} - c^{3} g^{3} h^{3}\right )} b^{3}} - \frac {{\left (3 \, d^{2} e g h n - c d e h^{2} n\right )} a^{2} - {\left (5 \, d^{2} e g^{2} n - c^{2} e h^{2} n\right )} a b + {\left (5 \, c d e g^{2} n - 3 \, c^{2} e g h n\right )} b^{2} - 2 \, {\left (2 \, a b d^{2} e g h n - a^{2} d^{2} e h^{2} n - {\left (2 \, c d e g h n - c^{2} e h^{2} n\right )} b^{2}\right )} x}{{\left (d^{2} g^{4} h^{2} - 2 \, c d g^{3} h^{3} + c^{2} g^{2} h^{4}\right )} a^{2} - 2 \, {\left (d^{2} g^{5} h - 2 \, c d g^{4} h^{2} + c^{2} g^{3} h^{3}\right )} a b + {\left (d^{2} g^{6} - 2 \, c d g^{5} h + c^{2} g^{4} h^{2}\right )} b^{2} + {\left ({\left (d^{2} g^{2} h^{4} - 2 \, c d g h^{5} + c^{2} h^{6}\right )} a^{2} - 2 \, {\left (d^{2} g^{3} h^{3} - 2 \, c d g^{2} h^{4} + c^{2} g h^{5}\right )} a b + {\left (d^{2} g^{4} h^{2} - 2 \, c d g^{3} h^{3} + c^{2} g^{2} h^{4}\right )} b^{2}\right )} x^{2} + 2 \, {\left ({\left (d^{2} g^{3} h^{3} - 2 \, c d g^{2} h^{4} + c^{2} g h^{5}\right )} a^{2} - 2 \, {\left (d^{2} g^{4} h^{2} - 2 \, c d g^{3} h^{3} + c^{2} g^{2} h^{4}\right )} a b + {\left (d^{2} g^{5} h - 2 \, c d g^{4} h^{2} + c^{2} g^{3} h^{3}\right )} b^{2}\right )} x}\right )} B}{6 \, e} - \frac {B \log \left (\frac {{\left (b x + a\right )}^{n} e}{{\left (d x + c\right )}^{n}}\right )}{3 \, {\left (h^{4} x^{3} + 3 \, g h^{3} x^{2} + 3 \, g^{2} h^{2} x + g^{3} h\right )}} - \frac {A}{3 \, {\left (h^{4} x^{3} + 3 \, g h^{3} x^{2} + 3 \, g^{2} h^{2} x + g^{3} h\right )}} \]
1/6*(2*b^3*e*n*log(b*x + a)/(b^3*g^3*h - 3*a*b^2*g^2*h^2 + 3*a^2*b*g*h^3 - a^3*h^4) - 2*d^3*e*n*log(d*x + c)/(d^3*g^3*h - 3*c*d^2*g^2*h^2 + 3*c^2*d* g*h^3 - c^3*h^4) + 2*(3*a*b^2*d^3*e*g^2*n - 3*a^2*b*d^3*e*g*h*n + a^3*d^3* e*h^2*n - (3*c*d^2*e*g^2*n - 3*c^2*d*e*g*h*n + c^3*e*h^2*n)*b^3)*log(h*x + g)/((d^3*g^3*h^3 - 3*c*d^2*g^2*h^4 + 3*c^2*d*g*h^5 - c^3*h^6)*a^3 - 3*(d^ 3*g^4*h^2 - 3*c*d^2*g^3*h^3 + 3*c^2*d*g^2*h^4 - c^3*g*h^5)*a^2*b + 3*(d^3* g^5*h - 3*c*d^2*g^4*h^2 + 3*c^2*d*g^3*h^3 - c^3*g^2*h^4)*a*b^2 - (d^3*g^6 - 3*c*d^2*g^5*h + 3*c^2*d*g^4*h^2 - c^3*g^3*h^3)*b^3) - ((3*d^2*e*g*h*n - c*d*e*h^2*n)*a^2 - (5*d^2*e*g^2*n - c^2*e*h^2*n)*a*b + (5*c*d*e*g^2*n - 3* c^2*e*g*h*n)*b^2 - 2*(2*a*b*d^2*e*g*h*n - a^2*d^2*e*h^2*n - (2*c*d*e*g*h*n - c^2*e*h^2*n)*b^2)*x)/((d^2*g^4*h^2 - 2*c*d*g^3*h^3 + c^2*g^2*h^4)*a^2 - 2*(d^2*g^5*h - 2*c*d*g^4*h^2 + c^2*g^3*h^3)*a*b + (d^2*g^6 - 2*c*d*g^5*h + c^2*g^4*h^2)*b^2 + ((d^2*g^2*h^4 - 2*c*d*g*h^5 + c^2*h^6)*a^2 - 2*(d^2*g ^3*h^3 - 2*c*d*g^2*h^4 + c^2*g*h^5)*a*b + (d^2*g^4*h^2 - 2*c*d*g^3*h^3 + c ^2*g^2*h^4)*b^2)*x^2 + 2*((d^2*g^3*h^3 - 2*c*d*g^2*h^4 + c^2*g*h^5)*a^2 - 2*(d^2*g^4*h^2 - 2*c*d*g^3*h^3 + c^2*g^2*h^4)*a*b + (d^2*g^5*h - 2*c*d*g^4 *h^2 + c^2*g^3*h^3)*b^2)*x))*B/e - 1/3*B*log((b*x + a)^n*e/(d*x + c)^n)/(h ^4*x^3 + 3*g*h^3*x^2 + 3*g^2*h^2*x + g^3*h) - 1/3*A/(h^4*x^3 + 3*g*h^3*x^2 + 3*g^2*h^2*x + g^3*h)
Leaf count of result is larger than twice the leaf count of optimal. 1530 vs. \(2 (272) = 544\).
Time = 1.14 (sec) , antiderivative size = 1530, normalized size of antiderivative = 5.39 \[ \int \frac {A+B \log \left (e (a+b x)^n (c+d x)^{-n}\right )}{(g+h x)^4} \, dx=\text {Too large to display} \]
1/3*B*b^4*n*log(abs(b*x + a))/(b^4*g^3*h - 3*a*b^3*g^2*h^2 + 3*a^2*b^2*g*h ^3 - a^3*b*h^4) - 1/3*B*d^4*n*log(abs(d*x + c))/(d^4*g^3*h - 3*c*d^3*g^2*h ^2 + 3*c^2*d^2*g*h^3 - c^3*d*h^4) - 1/3*B*n*log(b*x + a)/(h^4*x^3 + 3*g*h^ 3*x^2 + 3*g^2*h^2*x + g^3*h) + 1/3*B*n*log(d*x + c)/(h^4*x^3 + 3*g*h^3*x^2 + 3*g^2*h^2*x + g^3*h) + 1/3*(3*B*b^3*c*d^2*g^2*n - 3*B*a*b^2*d^3*g^2*n - 3*B*b^3*c^2*d*g*h*n + 3*B*a^2*b*d^3*g*h*n + B*b^3*c^3*h^2*n - B*a^3*d^3*h ^2*n)*log(h*x + g)/(b^3*d^3*g^6 - 3*b^3*c*d^2*g^5*h - 3*a*b^2*d^3*g^5*h + 3*b^3*c^2*d*g^4*h^2 + 9*a*b^2*c*d^2*g^4*h^2 + 3*a^2*b*d^3*g^4*h^2 - b^3*c^ 3*g^3*h^3 - 9*a*b^2*c^2*d*g^3*h^3 - 9*a^2*b*c*d^2*g^3*h^3 - a^3*d^3*g^3*h^ 3 + 3*a*b^2*c^3*g^2*h^4 + 9*a^2*b*c^2*d*g^2*h^4 + 3*a^3*c*d^2*g^2*h^4 - 3* a^2*b*c^3*g*h^5 - 3*a^3*c^2*d*g*h^5 + a^3*c^3*h^6) - 1/6*(4*B*b^2*c*d*g*h^ 3*n*x^2 - 4*B*a*b*d^2*g*h^3*n*x^2 - 2*B*b^2*c^2*h^4*n*x^2 + 2*B*a^2*d^2*h^ 4*n*x^2 + 9*B*b^2*c*d*g^2*h^2*n*x - 9*B*a*b*d^2*g^2*h^2*n*x - 5*B*b^2*c^2* g*h^3*n*x + 5*B*a^2*d^2*g*h^3*n*x + B*a*b*c^2*h^4*n*x - B*a^2*c*d*h^4*n*x + 5*B*b^2*c*d*g^3*h*n - 5*B*a*b*d^2*g^3*h*n - 3*B*b^2*c^2*g^2*h^2*n + 3*B* a^2*d^2*g^2*h^2*n + B*a*b*c^2*g*h^3*n - B*a^2*c*d*g*h^3*n + 2*B*b^2*d^2*g^ 4*log(e) - 4*B*b^2*c*d*g^3*h*log(e) - 4*B*a*b*d^2*g^3*h*log(e) + 2*B*b^2*c ^2*g^2*h^2*log(e) + 8*B*a*b*c*d*g^2*h^2*log(e) + 2*B*a^2*d^2*g^2*h^2*log(e ) - 4*B*a*b*c^2*g*h^3*log(e) - 4*B*a^2*c*d*g*h^3*log(e) + 2*B*a^2*c^2*h^4* log(e) + 2*A*b^2*d^2*g^4 - 4*A*b^2*c*d*g^3*h - 4*A*a*b*d^2*g^3*h + 2*A*...
Time = 5.90 (sec) , antiderivative size = 1183, normalized size of antiderivative = 4.17 \[ \int \frac {A+B \log \left (e (a+b x)^n (c+d x)^{-n}\right )}{(g+h x)^4} \, dx=\frac {B\,d^3\,n\,\ln \left (c+d\,x\right )}{3\,c^3\,h^4-9\,c^2\,d\,g\,h^3+9\,c\,d^2\,g^2\,h^2-3\,d^3\,g^3\,h}-\frac {\ln \left (g+h\,x\right )\,\left (h^2\,\left (B\,a^3\,d^3\,n-B\,b^3\,c^3\,n\right )-h\,\left (3\,B\,a^2\,b\,d^3\,g\,n-3\,B\,b^3\,c^2\,d\,g\,n\right )+3\,B\,a\,b^2\,d^3\,g^2\,n-3\,B\,b^3\,c\,d^2\,g^2\,n\right )}{3\,a^3\,c^3\,h^6-9\,a^3\,c^2\,d\,g\,h^5+9\,a^3\,c\,d^2\,g^2\,h^4-3\,a^3\,d^3\,g^3\,h^3-9\,a^2\,b\,c^3\,g\,h^5+27\,a^2\,b\,c^2\,d\,g^2\,h^4-27\,a^2\,b\,c\,d^2\,g^3\,h^3+9\,a^2\,b\,d^3\,g^4\,h^2+9\,a\,b^2\,c^3\,g^2\,h^4-27\,a\,b^2\,c^2\,d\,g^3\,h^3+27\,a\,b^2\,c\,d^2\,g^4\,h^2-9\,a\,b^2\,d^3\,g^5\,h-3\,b^3\,c^3\,g^3\,h^3+9\,b^3\,c^2\,d\,g^4\,h^2-9\,b^3\,c\,d^2\,g^5\,h+3\,b^3\,d^3\,g^6}-\frac {B\,\ln \left (\frac {e\,{\left (a+b\,x\right )}^n}{{\left (c+d\,x\right )}^n}\right )}{3\,h\,\left (g^3+3\,g^2\,h\,x+3\,g\,h^2\,x^2+h^3\,x^3\right )}-\frac {B\,b^3\,n\,\ln \left (a+b\,x\right )}{3\,a^3\,h^4-9\,a^2\,b\,g\,h^3+9\,a\,b^2\,g^2\,h^2-3\,b^3\,g^3\,h}-\frac {\frac {2\,A\,a^2\,c^2\,h^4+2\,A\,b^2\,d^2\,g^4+2\,A\,a^2\,d^2\,g^2\,h^2+2\,A\,b^2\,c^2\,g^2\,h^2+3\,B\,a^2\,d^2\,g^2\,h^2\,n-3\,B\,b^2\,c^2\,g^2\,h^2\,n-4\,A\,a\,b\,c^2\,g\,h^3-4\,A\,a\,b\,d^2\,g^3\,h-4\,A\,a^2\,c\,d\,g\,h^3-4\,A\,b^2\,c\,d\,g^3\,h+8\,A\,a\,b\,c\,d\,g^2\,h^2+B\,a\,b\,c^2\,g\,h^3\,n-5\,B\,a\,b\,d^2\,g^3\,h\,n-B\,a^2\,c\,d\,g\,h^3\,n+5\,B\,b^2\,c\,d\,g^3\,h\,n}{2\,\left (a^2\,c^2\,h^4-2\,a^2\,c\,d\,g\,h^3+a^2\,d^2\,g^2\,h^2-2\,a\,b\,c^2\,g\,h^3+4\,a\,b\,c\,d\,g^2\,h^2-2\,a\,b\,d^2\,g^3\,h+b^2\,c^2\,g^2\,h^2-2\,b^2\,c\,d\,g^3\,h+b^2\,d^2\,g^4\right )}+\frac {x\,\left (-B\,n\,a^2\,c\,d\,h^4+5\,B\,n\,a^2\,d^2\,g\,h^3+B\,n\,a\,b\,c^2\,h^4-9\,B\,n\,a\,b\,d^2\,g^2\,h^2-5\,B\,n\,b^2\,c^2\,g\,h^3+9\,B\,n\,b^2\,c\,d\,g^2\,h^2\right )}{2\,\left (a^2\,c^2\,h^4-2\,a^2\,c\,d\,g\,h^3+a^2\,d^2\,g^2\,h^2-2\,a\,b\,c^2\,g\,h^3+4\,a\,b\,c\,d\,g^2\,h^2-2\,a\,b\,d^2\,g^3\,h+b^2\,c^2\,g^2\,h^2-2\,b^2\,c\,d\,g^3\,h+b^2\,d^2\,g^4\right )}+\frac {x^2\,\left (B\,n\,a^2\,d^2\,h^4-2\,B\,g\,n\,a\,b\,d^2\,h^3-B\,n\,b^2\,c^2\,h^4+2\,B\,g\,n\,b^2\,c\,d\,h^3\right )}{a^2\,c^2\,h^4-2\,a^2\,c\,d\,g\,h^3+a^2\,d^2\,g^2\,h^2-2\,a\,b\,c^2\,g\,h^3+4\,a\,b\,c\,d\,g^2\,h^2-2\,a\,b\,d^2\,g^3\,h+b^2\,c^2\,g^2\,h^2-2\,b^2\,c\,d\,g^3\,h+b^2\,d^2\,g^4}}{3\,g^3\,h+9\,g^2\,h^2\,x+9\,g\,h^3\,x^2+3\,h^4\,x^3} \]
(B*d^3*n*log(c + d*x))/(3*c^3*h^4 - 3*d^3*g^3*h + 9*c*d^2*g^2*h^2 - 9*c^2* d*g*h^3) - (log(g + h*x)*(h^2*(B*a^3*d^3*n - B*b^3*c^3*n) - h*(3*B*a^2*b*d ^3*g*n - 3*B*b^3*c^2*d*g*n) + 3*B*a*b^2*d^3*g^2*n - 3*B*b^3*c*d^2*g^2*n))/ (3*a^3*c^3*h^6 + 3*b^3*d^3*g^6 - 3*a^3*d^3*g^3*h^3 - 3*b^3*c^3*g^3*h^3 - 9 *a^2*b*c^3*g*h^5 - 9*a*b^2*d^3*g^5*h - 9*a^3*c^2*d*g*h^5 - 9*b^3*c*d^2*g^5 *h + 9*a*b^2*c^3*g^2*h^4 + 9*a^2*b*d^3*g^4*h^2 + 9*a^3*c*d^2*g^2*h^4 + 9*b ^3*c^2*d*g^4*h^2 + 27*a*b^2*c*d^2*g^4*h^2 - 27*a*b^2*c^2*d*g^3*h^3 - 27*a^ 2*b*c*d^2*g^3*h^3 + 27*a^2*b*c^2*d*g^2*h^4) - (B*log((e*(a + b*x)^n)/(c + d*x)^n))/(3*h*(g^3 + h^3*x^3 + 3*g^2*h*x + 3*g*h^2*x^2)) - (B*b^3*n*log(a + b*x))/(3*a^3*h^4 - 3*b^3*g^3*h + 9*a*b^2*g^2*h^2 - 9*a^2*b*g*h^3) - ((2* A*a^2*c^2*h^4 + 2*A*b^2*d^2*g^4 + 2*A*a^2*d^2*g^2*h^2 + 2*A*b^2*c^2*g^2*h^ 2 + 3*B*a^2*d^2*g^2*h^2*n - 3*B*b^2*c^2*g^2*h^2*n - 4*A*a*b*c^2*g*h^3 - 4* A*a*b*d^2*g^3*h - 4*A*a^2*c*d*g*h^3 - 4*A*b^2*c*d*g^3*h + 8*A*a*b*c*d*g^2* h^2 + B*a*b*c^2*g*h^3*n - 5*B*a*b*d^2*g^3*h*n - B*a^2*c*d*g*h^3*n + 5*B*b^ 2*c*d*g^3*h*n)/(2*(a^2*c^2*h^4 + b^2*d^2*g^4 + a^2*d^2*g^2*h^2 + b^2*c^2*g ^2*h^2 - 2*a*b*c^2*g*h^3 - 2*a*b*d^2*g^3*h - 2*a^2*c*d*g*h^3 - 2*b^2*c*d*g ^3*h + 4*a*b*c*d*g^2*h^2)) + (x*(B*a*b*c^2*h^4*n - B*a^2*c*d*h^4*n + 5*B*a ^2*d^2*g*h^3*n - 5*B*b^2*c^2*g*h^3*n - 9*B*a*b*d^2*g^2*h^2*n + 9*B*b^2*c*d *g^2*h^2*n))/(2*(a^2*c^2*h^4 + b^2*d^2*g^4 + a^2*d^2*g^2*h^2 + b^2*c^2*g^2 *h^2 - 2*a*b*c^2*g*h^3 - 2*a*b*d^2*g^3*h - 2*a^2*c*d*g*h^3 - 2*b^2*c*d*...